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How do I initiate a timed animation within an expression?
Hello,
I currently have an AECS3 expression that uses a control layer’s Red channel values to determine the y rotation of a 3d object (code attached).
It’s working great, but what I’d like to do is instead of having it switch instantly to 180 degrees when the condition is met, to initiate a six-frame rotation to 180 degrees.
How do I do that?
Thanks,
Thomas Horne
target = thisComp.layer("controller Comp 1");
color = target.sampleImage([transform.position[0],transform.position[1]], [.5,.5], true, time);if (color[0] == 0){
0;
}else{
180;
} -
4 Replies
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I haven’t had time to test this code (so buyer beware) but it will be something like this, where you loop back through time, frame by frame, to see how long the red value has been greater than zero. Then you just multiply the number of frames (maximum 6) times 30 to get your result.
target = thisComp.layer(“controller Comp 1”);
color = target.sampleImage([transform.position[0],transform.position[1]], [.5,.5], true, time);if (color[0] == 0){
0;
}else{
f = thisComp.frameDuration;
for (i = 1; i <= 6; i++){ color = target.sampleImage([transform.position[0],transform.position[1]], [.5,.5], true, time-i*f); if (color[0] > 0) break;
}
i*30;
}Dan
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Thanks so much for your time Dan! – doesn’t seem to be working though. objects get frozen at half rotation, or click back and forth, etc.
I did make sure that I copied it right, and tried modifying things, to no avail. I’ll keep messing around on this end, if you have any more moments to spend on this, I would be extremely grateful!
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Yes, I see a few problems. Try this:
target = thisComp.layer(“controller Comp 1”);
color = target.sampleImage([transform.position[0],transform.position[1]], [.5,.5], true, time);if (color[0] == 0){
0;
}else{
f = thisComp.frameDuration;
for (i = 1; i <= 6; i++){ t = time-i*f; p = transform.position.valueAtTime(t); color = target.sampleImage([p[0],p[1]], [.5,.5], true,t); if (color[0] == 0) break; } Math.min(i,6)*30; } Dan -
Dan,
You are the MAN. I guess everyone already knows that though! 🙂 Thanks so much for all the expression awesomeness over the years.
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