How do I do a complex if/else structure?

[Dan Ebberts]

Maybe like this:

idx = Math.round(effect(“Slider Control”)(“Slider”));
myArray = [10,25,50,100];
myArray[clamp(idx,0,myArray.length-1)]

Dan

[Colin Braley]

There is no super simple way to do something like this. Some people like to use something called a “switch statement” in situations like this. For instance, the psuedocode you wrote in in you post would look like this written as a switch statement:


switch ( slider ){
case 1:
10
case 2:
25
case 3:
50
case 4:
100
default:
100//if the slider wasn't 1 ,2, 3, or 4
}


Im not sure if this is the exact syntax you would use for a switch statement in javascipt, and i actully don’t even know if there is a switch constuct in javascript….however, most modern programming languages do have a switch construct.

Personally, I would never use a swich statement, I prefer just using if statements….I feel that while code using switch statements might be more concise it is more-error prone because people don’t use them as often. Also, there are a bunch of other issues that crop up when you forget to use the “break” keyword peoperly within a switch statement, but I dont think I’ll elaborate on that one…

Anyway, if you REALLY want to use switch statements, check out wikipedia and read about them…

https://en.wikipedia.org/wiki/Switch_statement

~Colin

http://www.colinbraley.com

[Erin Shelby]

Thanks Dan/Colin! I’ll give it a whirl.

-Erin

[Mike Clasby]

I can’t getColin’s to work, love Dan’s.

Here is an old style if/else, it needs hold keyframes:

First you need a Null named “control”. Add a Slider to the Null. Add this expression to Opacity:

n = thisComp.layer(“Null 1”).effect(“Slider Control”)(“Slider”);
if (n==1) {
10
} else if (n==2) {
25
} else if (n==3) {
50
} else if (n==4) {
100
} else {
0
}