getting cursor X and Y position

[Dan Ebberts]

Expressions don’t have any way to detect the position of the cursor. There may be another way to achieve what you want, but I don’t really understand what your end objective is.

Dan

[Nicholas Joseph]

Hi Dan
Thanks for the response. 🙂

I’m doing some stereoscopic work and I’m having trouble or should I say the client is having trouble seeing the pixel depth amounts that are set.

So I created a script that will create a white dot… 1pixel X 1 pixel which sits with the original footage. When I add the 3d glasses effect at the end of the displacement setup and stuff..That white dot becomes a RED and a BLUE dot(because of the 3dglasses and displacement). The distance between those 2 dots equals the amount of pixel depth.(so foreground elements the dots are closer to each other and BG they are further away) What I am trying to do…is some how find the RED and BLUE dots in a comp (its on a black solid so they are the only 2 pixels in the entire comp) and measure the distance.(only the horizontal distance)

What I was hoping is if I can get the cursor location and hook it up to the white dot so that the dot follows the cursor and gives feed back to a textLayer that shows the depth at the location of the cursor…but I am having trouble measuring the distance between the 2 dots now. Having the dot follow the mouse is going to be really slow because the comp is very heavy..so I have abandon that and just attached the dot to a Null…which works well.

Do you know how I can measure the distance between the 2 pixels…
I tried the sampleImage() but it gives me the color at a point instead of the location of the color in a comp.

I’m hoping for something like….

PixelRED = search the area for pixel with value RED <>
LocationOfRedPixel = X and Y position

PixelBLUE = search the area for pixel with value BLUE <>
LocationOfBLUEPixel = X and Y position

text = LocationOfRedPixel.X – LocationOfBLUEPixel.X

Is that possible with scripting and expressions? I am reading up on pixelBlender for more answers…but any you can offer would be super awesome!

Thanks Again,