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Finding an intersection of two lines and parenting it
Hi, I am attempting to create a Lissajous curve table like the example driven by expressions.
By rotating a point at different speeds around a circle and tracing the x and y position from each it will generate different curves.
What I am struggling with is finding the the intersection of the x and y guides in red to then parent a shape layer to and use something like trails to draw them https://aescripts.com/trails/
I have created the below by parenting the x and y guides to the radius of each circle that has a rotation applied and then offsetting it by the rotation speed so they don’t rotate.
Doing this removes the ability to easily access the x or y position of the guides as they are being driven by rotation which makes me question if this is the best method?
Thanks.
thisComp.layer("radius").transform.rotation*-1thisComp.layer("radius").transform.rotation*-1.5-90
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2 Replies
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Hi,
this should work just fine, you need to access the global position of your guides. I made a setup parenting a small white circle on an outlined one, driven by the rotation:
xC=thisComp.layer("x1c"); //small white circle 1; For the X value
yC=thisComp.layer("y1c"); //small white circle 2; For the Y value
x=xC.toComp(xC.anchorPoint)[0]; //getting the global X value
y=yC.toComp(yC.anchorPoint)[1]; //getting the global Y value
[x,y]I added this expression to the position of a null which then I can trace using Write-on or the plugin you linked.
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Hi Robert
This worked perfectly, thank you so much.
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