Find the Largest of 3 Values

[Jon Smith]

Okay, after taking a deep breath and diving back in, I’ve figured out how to get the largest value.

if (a > b) {
if (a > c){
v = a
}
else {
if (c > b){
v = c
}
}
}

else {
if (b>c){
v = b
}
else{
v = c
}
}

[Kevin Camp]

i think you could do it with this:

Math.max(Math.max(a,b),c);

if you needed more values, you’d need to embed them in more Math.max() functions, ex:

Math.max(Math.max(Math.max(a,b),c),d);

Kevin Camp
Senior Designer
KCPQ, KMYQ & KRCW

[Dan Ebberts]

Math.max is designed to take as many parameters as you want to throw at it. This should work:

Math.max(a,b,c)

I seem to recall there was a version of AE where this didn’t quite work as advertised, but I’d say try it and see if it works for you.

Dan

[Kevin Camp]

you know, i’ve always thought it should work that way, but never tried it — though i’ve rarely needed it…

thanks.

Kevin Camp
Senior Designer
KCPQ, KMYQ & KRCW

[Kevin Camp]

well… it doesn’t seem to work as advertised in cs4. it only seemed to compare the first 2 values.

Kevin Camp
Senior Designer
KCPQ, KMYQ & KRCW

[Jon Smith]

Thanks a bunch. That’s much simpler. Looks like you do need to nest it the way Kevin has it. Any thoughts on how to get the middle value?

[Dan Ebberts]

Yeah, it looks like it didn’t get fixed until CS6. Safer to do it your way.

Dan

[Kevin Camp]

i think this would work…

vals = [a,b,c];
max = Math.max(Math.max(a,b),c);
min = Math.min(Math.min(a,b),c);
for (i = 0; i < vals.length; i++){
if (vals[i] > min && vals[i] < max) mid = vals[i];
}
mid

Kevin Camp
Senior Designer
KCPQ, KMYQ & KRCW

[Jon Smith]

Seems to work unless there are equal values then the expression breaks. Is there a way around that?

[Xavier Gomez]

Try this:

max = Math.max(Math.max(a,b),c);
min = Math.min(Math.min(a,b),c);
if (a < max){
if (a > min) mid=a else mid=Math.min(b,c);
}
else {mid = Math.max(b,c)};
mid

It will hardly generalize to higher number of parameters but for just 3 it is ok.