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Expression to link shape object ‘paths’ but minus x pixels
Hi,
I need the correct expression to link the paths of two shape layer shapes, but such that one is x pixels smaller than the other, thus creating in inner and outer box as in the example pick.
I want to move the path of only one of the shapes (when reshaping box) and have the other move also, keeping the same separation of n pixels.
If I simply scale the shape objects when parented then the width of the stroke obviously changes which isn’t desirable.
I tried something like:
ON THE SHAPE LAYER PATH TO BE THE CHILD –
base=thisComp.layer(“BASE”).content(“Shape 1”).content(“Path 1”).path;
[base[0],base[1]]-[3,-3]…but my understanding of the array coding mathematically is wrong.
Any guidance would be good. Thanks
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3 Replies
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I don’t think there’s any way to do math on a path shape. I think valueAtTime() is the only tool in the toolbox, and I don’t think it helps for your situation.
Dan
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I’m sure Dan is right about the expression. But what if you precomposed it, duplicated it, scaled one down, and then generated a stroke on the smaller precomp so that it matched the sizing of the other? Might not be perfect, but could potentially work.
“|_ (°_0) _|”
Sincerely,
George
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I’ve linked 2 shape layers with a couple of sliders and a simple expression here, this may work for you.
Here’s a CS6 version of the file:
….And another version with the shapes in a single layer grouped.
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