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experssion?
is this possible with an expression…
I need a layer (layer B) to follow in position another layers (layer A) right edge.
So when Layer A is scaled, Layer B moves in space to follow the right edge of layer A. The same would go for when Layer A is rotated or repostioned, Layer B would stay snapped to layer A’s right edge.
I can not use parenting here, because I do not want the layer B to be scaled by layer A, only re-po’d.
this make sense?
basically I am creating a rainbow ribbon in many segments that I need to accordion, and want to stretch certain sections longer than others, while maintaining the connections. The thickness (height) of the ribbon can not change. -
3 Replies
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i’m sure ther is a much more elegant way to write this…. but using the pickwhip, i was able to create this expression:
x = thisComp.layer(“Layer A”).transform.position[0] + ((width + ((thisComp.layer(“Layer A”).width) * (thisComp.layer(“Layer A”).transform.scale[0])/100))/2);
y = transform.position[1];
[x,y]
like i said, its ugly, but works…
Kevin Camp
Designer – KCPQ, KMYQ & KRCW -
Nice expression. It worked fine for me…
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ok, i had some time today…
here is a version that will look at the layer below it, so it can be pasted into one layer and then duplicated… each duiplicate’s x position will then be based on the layer below it….
L = thisComp.layer(index + 1);
x = L.transform.position[0] + (((width * (transform.scale[0] / 100)) + ((L.width) * (L.transform.scale[0]) / 100)) / 2);
y = transform.position[1];[x,y]
Kevin Camp
Designer – KCPQ, KMYQ & KRCW
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