Creating a stretchy chain of objects

[Emre Anil]

Assuming t1 and t2 are the Yellow Null Objects:

First Red Null Object’s position expression:
n1 = thisComp.layer("t1").transform.position;
n2 = thisComp.layer("t2").transform.position;
pX = n1[0] - ((n1[0] - n2[0]) / 3 * 2);
pY = n1[1] - ((n1[1] - n2[1]) / 3 * 2);
[pX, pY]

Second Red Null Object’s position expression:

n1 = thisComp.layer("t1").transform.position;
n2 = thisComp.layer("t2").transform.position;
pX = n1[0] - ((n1[0] - n2[0]) / 3);
pY = n1[1] - ((n1[1] - n2[1]) / 3);
[pX, pY]

[William Anugerah]

Thank you very much! While it does exactly what I wanted, it does reposition the middle (red null) objects into equal distances, which is not quite ideal because my objects are initially laid out in a different ratio.

I was able to easily offset the resulting position by adding value to the last line ( [xx+pX, yy+pY] ) until they match their initial position, but is there any other way to work this out while keeping the objects’s initial position intact?

[Emre Anil]

I divided the position difference by 3 for the even spacing. changing it according to your ratio should work.