Creating a Shape Path Tween

[Alex Printz]

You can do it with a linear interpolation. you can change linear to ease if you want below, or try to implement penner easing with some more complex functions.

If you wanted to use keyframes instead of different paths, you would generate two different times (ta, tb) using key(1).time, key(2).time, and then instead generate Pa/Ta/Oa using ta instead of t, and the same thing for B sets.

You miiiight be able to try:


P = linear(m,0,1,Pa,Pb);
T = linear(m,0,1,Ta,Tb);
O = linear(m,0,1,Oa,Ob);


but I am unsure if it will work, not at a workstation to test if linear can handle longer arrays.

A = thisComp.layer("path A").content("group 1").content("Path 1").path; //path A point
B = thisComp.layer("path B").content("group 1").content("Path 1").path; //path B point;
m = .5 // percent to morph between them
t = time; //sets the time to grab

Pa = A.points(t); //points for path A
Ta = A.inTangents(t); inTangents for path A
Oa = A.outTangents(t); outTangents for path A

Pb = B.points(t);
Tb = B.inTangents(t);
Ob = B.outTangents(t);

P = []; //final points
T = []; //final inTangents
O = []; //final outTangents

for(i=0; i<Pa.length; i++){ //linearizes all properties for each point
P.push(linear(m,0,1,Pa[i],Pb[i]));
T.push(linear(m,0,1,Ta[i],Tb[i]));
O.push(linear(m,0,1,Oa[i],Ob[i]));
}
createPath(P,T,O,A.isClosed()); //creates new path, checks if A was closed

Alex Printz
Mograph Designer

[Dan Ebberts]

I think this will work:


p1 = content("Shape 1").content("Path 1").path;
p2 = content("Shape 2").content("Path 1").path;
v1 = p1.points();
v2 = p2.points();
tIn1 = p1.inTangents();
tIn2 = p2.inTangents();
tOut1 = p1.outTangents();
tOut2 = p2.outTangents();
v = [];
tIn = [];
tOut = [];
for (i = 0; i < v1.length; i++){
v[i] = (v1[i]+v2[i])/2;
tIn[i] = (tIn1[i]+tIn2[i])/2;
tOut[i] = (tOut1[i]+tOut2[i])/2;
}
createPath(v,tIn,tOut,p1.isClosed())


Dan

[Jason Guest]

Amazing! Thanks very much guys, this is one I definitely wouldn’t have figured out by myself.

Alex, I tried yours first and it worked straight out of the box. I’ll have a play with yours too, Dan and hopefully I’ll be able to make sense of how they both work!

I really appreciate your efforts, thank you.

Jason