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Creating a dissolve between numbers in counter expression
Posted by Ian Ellerby on January 27, 2015 at 11:34 amHi
I’m using a counter expression, going from 1-1000 in 1000 seconds, so one number per second, and would like a dissolve between these numbers, does anyone know if this is possible? I can’t work this one out.
Be grateful of any thoughts.
Thanks IanIan Ellerby replied 11 years, 3 months ago 2 Members · 5 Replies -
5 Replies
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Dan Ebberts
January 27, 2015 at 8:17 pmHere’s one way.
1. Create a text layer.
2. Duplicate it.
3. To the top copy’s Source Text property, add this expression:
Math.floor(time)+1;
4. To the top copy’s Opacity property, add this expression:
tFade = .25;
t = time%1;
linear(t,1-tFade,1,100,0)5. To the bottom copy’s Source Text property, add this expression:
tFade = .25;
Math.floor(time+tFade)+1;Dan
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Ian Ellerby
January 28, 2015 at 11:50 amWow Dan, that’s great, thanks so much for sending this.
It has more of a pulsing dissolve than a gradual dissolve, which is really working for me as I’m also trying to create a one second heart beat pulse change here. I’ve tweaked the tFade = .25; a little.
Really do appreciate your help here.
Thanks
Ian -
Ian Ellerby
January 29, 2015 at 12:29 pmHi Dan
I’m trying to tweak the time property between each change of numbers. At the moment it changes every 1 sec per number, I’d like to increase this to say 1.5 secs. I can’t seem to change any value to make this happen. Do I need to add another line of expression?
If you get a moment
Thanks Ian -
Dan Ebberts
January 29, 2015 at 5:59 pmI think this will work better.
Top layer Source Text:
dur = 1.5;
Math.floor(time/dur)+1;Top layer Opacity:
dur = 1.5;
tFade = .5;
t = time%dur;
linear(t,dur-tFade,dur,100,0)Bottom layer Source Text:
dur = 1.5
tFade = .5;
Math.floor((time+tFade)/dur)+1;Bottom layer Opacity
dur = 1.5;
tFade = .5;
t = time%dur;
linear(t,dur-tFade,dur,0,100)Dan
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Ian Ellerby
January 29, 2015 at 6:16 pmThanks very much Dan, it looks good. Sort of understand what you’ve done.
Do appreciate your help. I’m sure a lot of guys new to expressions do also.
Thanks Ian
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