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Counter rounding and then no rounding?
I’m using this expression as a counter, and I want it to round while counting, but not round upon finishing (so it ends on 3.9). Any suggestions? I thought this would be easier than it’s ended up being :/
timeA = 0; timeB = 1; Math.round(linear(time, timeA,timeB, 0, 3.9))+'%'; -
2 Replies
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Something like this maybe:
timeA = 0;
timeB = 1;
val = Math.round(linear(time, timeA,timeB, 0, 3.9));
(val > 3 ? 3.9 : val)+’%’Dan
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Thanks Dan, that’s an elegant solution!
By chance do you know a better way to achieve the same thing?
I always like to see if there’s a better way of achieving my messes.Thanks again.
D. Walters
Graphic Artist – WWAY
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