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Controlling an offset position with an angle slider.
Hey smart people,
I’m wondering if there’s an elegant way to controlling a layers position using angles & magnitudes as opposed to cartesian coordinates.
And if not, is there a breakdown somewhere of how turn angle inputs into x/y outputs. From my floundering research thus far noticed there’s a lot of radian conversions & if/then statements for the 4 quadrants but I haven’t been able to parse it beyond that.
For reference, Dan Ebberts code here almost does what I’m trying to figure out, but I can’t quite deconstruct it in order to control the distance of the offset.
Thanks,
EDIT: After a bit more searching I came across GrayMachine’s polar coordinate code. It took a bit of tinkering but I got it to work for myself. However, set the resting position of the layer (that is, the position when the Distance1 slider was 0) at 971,971. Subtracted 11 from 2 lines of code & that managed to work, but I don’t really know /why/.
d = thisComp.layer(“Master”).effect(“Distance1”)(“Slider”)
a = thisComp.layer(“Master”).effect(“Angle Control”)(“Angle”)angle = a;
length = d;
aRad =degreesToRadians( angle – 90);
x=d*Math.cos(aRad)-11;
y=d*Math.sin(aRad)-11;
add(position, [x, y]); -
2 Replies
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It should be as straightforward as this:
a = effect(“Angle Control”)(“Angle”);
d = effect(“Slider Control”)(“Slider”);
r = degreesToRadians(a-90);
x = d*Math.cos(r);
y = d*Math.sin(r);
value + [x,y]which I think is the same as Harry’s solution. I’m not sure why you’d need any adjustments unless you’ve got parenting w/ rotation or non-uniform scaling involved.
Dan
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Yeah I’d only found it it after posting my question. I still don’t quite understand why an input of 0 gives me an offset position of +11, but I haven’t yet worked out that math.
But thanks for your time.
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