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Conditional statements with multiple values and multiple results
I have another expressions question. :slightly_smiling_face: I was wondering two things about if/else conditional statements. I have 4 values. I want to say that if a is greater than b, c, & d, then the width value = x and the height value = y. (There wouldn’t be a variable in the x & y spot – it would be a specific value). Then I want to do the same for b, c, & d.
My questions are:
A.) Is it possible to check which value is the greatest without having to write out if(a>b && a>c && a>d)? It’s a lot of typing. I’m fine typing it for each value, but I’m wondering if there’s a shortcut.
And
B.) Is it possible to have more than one result in a conditional statement? If so, how do I write it. I basically want to say, “If (a==true){width = x.width && height = y.height},” but that always produces errors. Is there a way to do this, or do I have to write the conditional statement twice, once for width and once for height?
Thank you!
UPDATE: I’ve tried 2 options, had some success with the first, none with the second:
1st Option:
a = thisComp.layer(“TEXT”).sourceRectAtTime();
b = thisComp.layer(“TEXT 2”).sourceRectAtTime();
c = thisComp.layer(“TEXT 3”).sourceRectAtTime();
d = thisComp.layer(“TEXT 4”).sourceRectAtTime();if(a>=b && a>=c && a>=d){
Width = a.width;
Height=a.height;
}else if(b>a && b>c && b>d){
Width = b.width;
Height = b.height;
}else if(c>a && c>b && c>d){
Width = c.width;
Height = c.height;
}else{
Width = d.width;
Height = d.height;p=thisComp.layer(“EFFECTS”).effect(“box margin”)(“Slider”);
if(Width!=0){
x=Width+p*10
}else{
x=0
}
y=Height+p;
[x,y]Attempt 2:
a = thisComp.layer(“TEXT”).sourceRectAtTime();
b = thisComp.layer(“TEXT 2”).sourceRectAtTime();
c = thisComp.layer(“TEXT 3”).sourceRectAtTime();
d = thisComp.layer(“TEXT 4”).sourceRectAtTime();mX = Math.max(a, b, c, d);
if(a == b && a == c && a == d){
Width = a.width;
Height = a.height;
}else{
Width = mX.width;
Height = mX.height;
}p=thisComp.layer(“EFFECTS”).effect(“box margin”)(“Slider”);
if(Width!=0){
x=Width+p*10
}else{
x=0
}
y=Height+p;
[x,y] -
1 Reply
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You can use Math.max() to compare multiple values, like this:
Width = Math.max(a.width, b.width, c.width, d.width);
That should help simplify things.
Dan
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