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Activity Forums Adobe After Effects Expressions cascading falling grid

  • cascading falling grid

    Posted by Jonas Espinoza on August 10, 2010 at 5:19 pm

    ok, one more little problem

    i have this 10×10 grid with each “clone” placed by hand, so they all have different positions. what i would like is something like the master controller layer inpoint offset technique**, but landing at their actual position, and not the same x,y as the controller null

    **
    t = time – inPoint;
    N = thisComp.layer(“fade in long”);
    N.transform.opacity.valueAtTime(N.inPoint + t)

    thanks so much, this is the best forum on the net

    Jonas Espinoza replied 15 years, 9 months ago 1 Member · 2 Replies
  • 2 Replies
  • Jonas Espinoza

    August 10, 2010 at 6:06 pm

    so my challenge in figuring this out, is i know its like a simple minus or plus operation to negate out the actual position of each layer to make them follow the control null, but keep their placement in the comp. all that needs to happen is for them to fall vertically down and land where i placed them, with controllable delay in the script

  • Jonas Espinoza

    August 10, 2010 at 6:56 pm

    figured out a workaround on my own… still trying to remember that piece of essential scripting skill to neutralize the individual positions of elements referencing a control null

    heres what i did – just had a slider animating and using it as a negative number. then put on the “inertial bounce” script thats floating around on the slider keys so everything bounces down. now i might add another varable with a random seed (#+index) to make each one fall a little different.

    t=time-inPoint;

    N=thisComp.layer(“dropper”);

    dropper=thisComp.layer(“dropper”).effect(“drop”)(“Slider”).valueAtTime(N.inPoint+t);

    d=value[1]-dropper;

    [value[0],d,value[2]]

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