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Can I simplify this expression?
Hi!
Ok, I connected my Source Text to my Text scale.To the scale, I applied this:
x = Math.abs(Math.sin(time)*100);
y = 100;
[x, y]Until here, no problem.
But my source text had a lot of numbers after the dot, like: 84,14709848…So I applied Math.round(transform.scale[0]) to round it.
But I wanted to simplify to 84,1 (84,14709848…) and not to 84 (example).
So I did this:
scale = transform.scale[0];
round = Math.round(scale);
d = (scale – round)*10;
dII = .1*Math.round (d);
fin = round + dII;fin
So, scale was the scale of my layer, and in “round” I rounded it (example: 84,14709848 to 84). In “d” I simply subtract scale and round (84,14709848… – 84 = 0,14709848…), to leave only the numbers after the decimal point and I multiplied them by 10 to give them and integer number (so 0,14709848… became 1,4709848…). In “dII” I round my 1,4709848… to 1 and I divided it by 10 (multiply by 0.1) so it became 0.1. So in “fin” I did the round (value in integers) plus the dII (the number with one number after the decimal point) to round 84,14709848 to 84,1.
And to round 84,14709848 to 84,14 I used this:
scale = transform.scale[0];
scale2 = scale*10
round = Math.round(scale2);
d = (scale2 – round)*10;
dII = .1*Math.round (d);
fin = (round + dII)*.1;fin
So, I have and impression that I can simplify this a lot. Is it possible or am I crazy?
Thank you,
Gustavo. -
5 Replies
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You’ll like this 🙂
transform.scale[0].toFixed(1)
Dan
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I almost fainted when I saw that, so simple, so easy…
I didn’t know toFixed till now, it is incredible to simplify numers (not as incredible as you, Dan).
It is a good think to add in your Expressioneer’s Design Guide, isn’t it?
Thank you very much!
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Yes, thanks for thanks for the suggestion. I’m working on one that uses toFixed();
Dan
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1/1+a^n + 1/1+a^-n
My attempt:
=1/1+a^n + 1+a^n/1
=1+{1+a^n(1+a^n)}/1+a^n
=1+1+2a^n+a^n^2/1+a^n
=2+2a^n+a^n^2/1+a^n
let a^n=m
=2+2m+2m^2/1+m
=2(1+m+m^2)/1+mI don’t know what to do next, the answer is supposed to be 1.
will you please simplify the expression its very urgent i tried on many sites but didn’t get the correct answer according to my mathematics textbook.
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How about this:
1/(1 + a^n) + 1/(1 + a^-n)
= ((1 + a^-n) + (1 + a^n))/((1 + a^n)*(1 + a^-n))
= (2 + a^n + a^-n)/(1 + a^n + a^-n + a^n*a^-n)
= (2 + a^n + a^-n)/(2 + a^n + a^-n)
= 1Dan
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