Can an expression acknowledge the Comp’s name?

[Darby Edelen]

[Bert Brown] “so for example i have a comp name:

PRIMEHD_P2_L2_TSS

and I want the expression to look for the number after that “L” and adjust a slider number (BAR LENGTH SLIDER) to match that digit. in this case “2””

I think this should get you most of the way there:


n = thisComp.name;
a = n.split("_");


a will be an array with the following values:


a[0] = PRIMEHD
a[1] = P2
a[2] = L2
a[3] = TSS

So to get the digit in a[2] you could use:

dig = a[2].charAt(1) * 1; //multiply by one to convert character to an integer

I haven’t tested this but I believe it should work.

Darby Edelen

[Bert Brown]

radical. works great. thanks so much

this is also really helpful for just understanding the way expressions can use text. i had never utilized split or charAt

if i wanted an expression to look at a character, like the “L” how would i do that? just not multiply by 1?

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[Dan Ebberts]

Another way:

n = thisComp.name;
parseInt(n[n.indexOf(“_L”) + 2],10)

Dan

[Lloyd Alvarez]

c=thisComp.name
c.charAt(c.lastIndexOf("_")-1)

Since we’re doing remixes, here’s my take on it 😉

-Lloyd

https://aescripts.com

[Lloyd Alvarez]

forgot that it needed to be used as a number:

c=thisComp.name
parseInt(c.charAt(c.lastIndexOf(“_”)-1),10)

BTW, just recently learned about the various flavors of parseInt so if you are following along at home, make sure to add the ,10 whenever you use parseInt to make sure you pull base 10 numbers which I imagine is what you’ll want 99% of the time..

-Lloyd

https://aescripts.com

[Darby Edelen]

In a case where there is not a need to convert from an arbitrary base to decimal, wouldn’t multiplying or dividing by 1 be easier to implement? And also decrease the chances of accidentally misinterpreting the string as octal?

Darby Edelen

[Dan Ebberts]

Good point. In a case like this it would make sense to take advantage of JavaScript’s implict type conversions. I think I’d use 0 + though. Just like you can convert a number to a string like this:

n = 1234.567;
“” + n;

You could go the other way like this:

str = “1234.567”;
0 + str;

Dan

[Lloyd Alvarez]

I love the fact that I am always learning new things from you guys. 🙂

-Lloyd

https://aescripts.com