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Overshoot Bounce Out Expression Needed!
I’ve discovered a lot of great expressions on the internet for a realistic bounce overshoot animation. The best one, and the one I’m going with is from Dan: https://www.motionscript.com/articles/bounce-and-overshoot.html
However, I’m looking for a “bounce out” overshoot expression- essentially just the reverse of the bounce in, where it bounces very little at the beginning and gradually gets larger before flying out to it’s final position. Simply reversing the inputs of the expression does not work.
I need this in expression form so that I can link certain values to sliders. Anyone have any resources or ideas on how to accomplish this?
Here is the bounce in animation from Dan that I am using:
freq = 3; decay = 5; t = time - inPoint; startVal = [0,0]; endVal = [200,200]; dur = 0.1; if (t < dur){ linear(t,0,dur,startVal,endVal); }else{ amp = (endVal - startVal)/dur; w = freq*Math.PI*2; endVal + amp*(Math.sin((t-dur)*w)/Math.exp(decay*(t-dur))/w); }motionscript.com
Realistic Bounce and Overshoot
Dan Ebberts's resource for After Effects scripting and expressions
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3 Replies
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To run it in reverse, you need to define an end point, so you could introduce a new variable, totalDur, for that purpose, and modify one line of the expression to reverse it, like this:
freq = 3;
decay = 5;
totalDur = 3;
t = (inPoint +totalDur) - time;
startVal = [0,0];
endVal = [200,200];
dur = 0.1;
if (t < dur){
linear(t,0,dur,startVal,endVal);
}else{
amp = (endVal - startVal)/dur;
w = freq*Math.PI*2;
endVal + amp*(Math.sin((t-dur)*w)/Math.exp(decay*(t-dur))/w);
}You could tie any of the variables (first 3 lines) to sliders.
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This works! Thanks again, Dan!
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Thanks for solving this, Dan!
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