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Bounce out expression needed
Hi all,
I am looking for bouncing back or bounce out expression, I already have bounce in expression which good, but I need one for bouncing out
this is the one I am using for bounce inamp = .1;
freq = 2.0;
decay = 5.0;
n = 0;
time_max = 4;
if (numKeys > 0){
n = nearestKey(time).index;
if (key(n).time > time){
n–;
}}
if (n == 0){ t = 0;
}else{
t = time – key(n).time;
}
if (n > 0 && t < time_max){
v = velocityAtTime(key(n).time – thisComp.frameDuration/10);
value + v*amp*Math.sin(freq*t*2*Math.PI)/Math.exp(decay*t);
}else{value}
Thank you
replied 9 months, 3 weeks ago 2 Members · 1 Reply
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1 Reply
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That one is difficult to run backwards (if that’s what you meant) because there’s no definite end point, but maybe something like this would be useful:
val = value;
if (numKeys > 1){
n = nearestKey(time).index;
if (key(n).time > time) n--;
if ((n > 0) && (n < numKeys)){
d = key(n+1).time-key(n).time;
dv = key(n+1).value-key(n).value;
t = (time-key(n).time)/d;
val = key(n).value + dv*t*t*(2.70158*t - 1.70158);
}
}
val
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