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axis/expression problem
Hi guys
I have the following problem:
I have two layers in a comp. When I move layer1 in the x axis, layer2 should be moved in the y axis and should get the same y value as layer 1. I tried the following expression on the position property of layer2:
if (thisComp.layer(“layer1”).transform.position[0] == -102) {
transform.position[1] == thisComp.layer(“layer1”).transform.position[1];
}But this gets me an error message saying something like “Expression result must have dimension 2 not 1 (sorry, my AE is in german language).
Can anyone give me a tipp?
thanks
Cheers, Pascal
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5 Replies
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The way you have it set up, I would think you’d want it like this:
if (thisComp.layer(“layer1”).transform.position[0] == -102) {
[value[0], thisComp.layer(“layer1”).transform.position[1]];
}else{
value;
}This leaves the layer in its position until layer1 has an x value of exactly -102, then it jumps to the same y value as layer1. Is that what you wanted?
Dan
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Hi Dan
Yes, this is nearly what I was looking for. Many thanks!
But it would be great when layer 2 moves to its new position instead of just jumping from the old to the new position. Can you also give me a hint on that?Thanks,
Pascal -
Hi Dan
This is nearly the way it should work. Thank you very much. But is it also possible, to move layer2 to its new position instead of jumping?
Thanks,
Pascal -
Possible, but not simple. I think you’d have to write some code that would start at the current comp time and loop backwards through the comp until you found the time when layer1 arrived a y = -102, then calculate where layer2 should be now based on how long it’s been, how fast you want the move to occur, and the distance to be traveled.
Dan
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depending on what direction you are traveling you could use linear:
layer1position=thisComp.layer(“layer1”).transform.position;
if (layer1position[0] <= -98 && layer1position[0] >= -102) {
y=linear(layer1position[0],-102,-98,-102,value[1]);
[value[0], y];
}else{
value;
}-Lloyd
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