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Adding digits from Numbers filter
I’m low on time or I’d surf Dan’s site for this!
I don’t know if this is possible…
I have to update the Medal Count every day during the Olympics. The producer wants 3 columns (Gold, Silver, Bronze) and numbers below each that are changing randomly. We reveal the count by having each number lock into place, first Gold then Silver then Bronze. Then a “Total” Medal sum appears in RED.I’m using the effect: Effects>Text>Numbers to generate the number info
Settings:
“Type”is set to:Number
“Decimal Places”is set to: 0 and
“Value/Offset/Random”is set to: whatever Medal count I put in i.e. 435 (random is unchecked).I’d love to create an expression that adds the 3 numbers together and automatically applies the sum to my RED “Total” layer. The red layer doesn’t appear until the 3 digits stop animating so if this expression causes the RED number to animate, that’s ok!
I hope this makes sense. Any pointers would be great.
Thanks, Chris
Chris Heuer
Freefall FX, LLC -
4 Replies
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Unless I’m missing something, the expression for the total will look something like this (assuming all instances of the Numbers effect are applied to the same layer):
gold = effect(“Numbers”)(“Value/Offset/Random Max”);
silver = effect(“Numbers 2”)(“Value/Offset/Random Max”);
bronze = effect(“Numbers 3”)(“Value/Offset/Random Max”);
gold + silver + bronzeDan
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I was hoping to do it with one 3 digit instance of the numbers effect but after seeing your expression, I see how that probably doesn’t work. I’ll make an instance for each number and your expression should work perfectly!
Thanks, Chris
Chris Heuer
Freefall FX, LLC -
If you just want to add up the digit from one Numbers effect, this should work:
s = Math.round(effect(“Numbers”)(“Value/Offset/Random Max”)).toString();
total = 0;
for (i = 0; i < s.length; i++){ total += parseInt(s[i],10); } total Dan -
I’m going to try that just for the learning. I turns out that the expression you gave me with 3 instances is the perfect solution because the medal counts should go into double digits. 3 double digit instances of the Numbers effect with your expression works perfectly!
Thanks for the revised expression. I’ll put it to good use.
Chris
Chris Heuer
Freefall FX, LLC
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