• Adobe After Effects

  experssion?

  Posted by Accountclosedduetonorealnameused on August 6, 2007 at 8:11 pm

  is this possible with an expression…

  I need a layer (layer B) to follow in position another layers (layer A) right edge.

  So when Layer A is scaled, Layer B moves in space to follow the right edge of layer A. The same would go for when Layer A is rotated or repostioned, Layer B would stay snapped to layer A’s right edge.

  I can not use parenting here, because I do not want the layer B to be scaled by layer A, only re-po’d.

  this make sense?
  basically I am creating a rainbow ribbon in many segments that I need to accordion, and want to stretch certain sections longer than others, while maintaining the connections. The thickness (height) of the ribbon can not change.

  Kevin Camp replied 19 years ago 3 Members · 3 Replies
• 3 Replies

• 

  Kevin Camp

  August 6, 2007 at 9:10 pm

  i’m sure ther is a much more elegant way to write this…. but using the pickwhip, i was able to create this expression:

  x = thisComp.layer(“Layer A”).transform.position[0] + ((width + ((thisComp.layer(“Layer A”).width) * (thisComp.layer(“Layer A”).transform.scale[0])/100))/2);

  y = transform.position[1];

  [x,y]

  like i said, its ugly, but works…

  Kevin Camp
  Designer – KCPQ, KMYQ & KRCW
• 

  Lord Scales

  August 6, 2007 at 11:46 pm

  Nice expression. It worked fine for me…
• 

  Kevin Camp

  August 7, 2007 at 8:24 pm

  ok, i had some time today…

  here is a version that will look at the layer below it, so it can be pasted into one layer and then duplicated… each duiplicate’s x position will then be based on the layer below it….

  L = thisComp.layer(index + 1);
  x = L.transform.position[0] + (((width * (transform.scale[0] / 100)) + ((L.width) * (L.transform.scale[0]) / 100)) / 2);
  y = transform.position[1];

  [x,y]

  Kevin Camp
  Designer – KCPQ, KMYQ & KRCW

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