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Struggling with if/else with color input
Hi there I have a simple expression:
col = content(“Group 2”).content(“Fill 1”).color; white = hexToRgb(“ffffff”); if(col == white){0;}else{100;}
I tried with 1 (=) sign or 3 (===) but then it just doesnt work when I change
the color input (meaning it stays 0% with white (good) but it doesnt
show 100% if it is any other color…(bad))any help is appreciated.
cheers
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4 Replies
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It should work if you change your last line to this:
col.toString() == white.toString() ? 0 : 100
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Wow that worked like a charm.
Thanks so much.
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Just curious, why does that look so
different than the if/else statements
I know..?
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Greetings from Switzerland -
When they changed AE’s JavaScript engine, it would no longer accept single-line if-else statements without the full curly bracket treatment, so I pretty much switched to the conditional (ternary) ? : operator, which is a kind of if-else shorthand.
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Thank you for the solve, Dan!
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