• Adobe After Effects Expressions

  Parent single path to two other paths and blend between them with slider control

  Posted by BayarUgrakh Batzorig on August 8, 2022 at 1:56 pm

  Parent one path to two other animated paths and morph between them with slider control would be nice.

  

  BayarUgrakh Batzorig replied 3 years, 11 months ago 2 Members · 2 Replies
• 2 Replies

• 

  Dan Ebberts

  August 8, 2022 at 7:24 pm

  This is pretty limited and not well tested. If the two paths don’t have the same number of points, it doesn’t do anything. It assumes that the slider is on the layer with the expression.

  path1 = thisComp.layer("Shape Layer 1").content("Shape 1").content("Path 1").path;
  path2 = thisComp.layer("Shape Layer 2").content("Shape 1").content("Path 1").path;
  s = effect("Slider Control")("Slider");
  p1 = path1.points();
  p2 = path2.points();
  it1 = path1.inTangents();
  it2 = path2.inTangents();
  ot1 = path1.outTangents();
  ot2 = path2.outTangents();
  if (p1.length == p2.length){
    newP = [];
    newIt = [];
    newOt = [];
    for (i = 0; i < p1.length; i++){
      newP.push(linear(s,0,100,p1[i],p2[i]));
      if (it1.length > 0 && it2.length > 0){
        newIt.push(linear(s,0,100,it1[i],it2[i]));
      }else if (it1.length > 0){
        newIt.push(linear(s,0,100,it1[i],[0,0]));
      }else if (it2.length > 0){
        newIt.push(linear(s,0,100,[0,0],it2[i]));
      }
      if (ot1.length > 0 && ot2.length > 0){
        newOt.push(linear(s,0,100,ot1[i],ot2[i]));
      }else if (ot1.length > 0){
        newOt.push(linear(s,0,100,ot1[i],[0,0]));
      }else if (ot2.length > 0){
        newOt.push(linear(s,0,100,[0,0],ot2[i]));
      }
    }
    createPath(newP,newIt,newOt,path1.isClosed());
  }else
    value;
• 

  BayarUgrakh Batzorig

  August 8, 2022 at 11:10 pm

  Thank you Dan, this is exactly what I wanted.

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