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  • Advice for SAN for 3 x FCP / 2 x XServe RAID

    Posted by Ben Cheng on February 10, 2006 at 8:16 am

    Hi guys,

    Wonder if you can help me out with the following :

    – 3 x FCP (1 x HD / 2 x SD)

    – 2 x XServe RAID (1 x 14 x 250GB / 1 x 7 x 500GB)

    – 1 x QLogic SANbox 5200-8

    – SANmp

    May I know whats the ideal config for the XServe RAIDs ?

    I’m thinkin of putting the 14-drive XServe RAID for the HD system, split the 7-drive XServe RAID among the 2 SD systems

    14-drive XServe >
    4 partitons/LUNs
    1 partiton/LUN from Channel A + 1 partiton/LUN from Channel B = 1 volume
    Total 2 volumes (1 for Media, 1 for Render)

    7-drive XServe >
    4 partitons/LUNs
    2 partitons/LUNs = 2 volumes
    Total 4 volumes (2 for Media, 2 for Render)

    Will the 14-drive XServe RAID be able playback 1 x HD stream + 2 x SD streams (for the SD systems) at the same time ?

    Is the 7-drive XServe RAID sufficient for the 2 SD systems ?

    Any advice is greatly appreciated !

    Cheers
    Ben Cheng

    Ben Cheng replied 20 years, 2 months ago 2 Members · 2 Replies
  • 2 Replies
  • Nate Cooper

    February 12, 2006 at 8:18 am

    Ben,

    I assume you are talking about uncompressed HD and SD. If so, for a stream of uncompressed HD you will need to do a single RAID 50 of the entire Xserve RAID (2 x 7_disk RAID5’s striped as a single volume), any other configuration will most likely not handle uncompressed HD. Adding SD onto the same RAID will not happen, you’ll be dropping frames like it’s going out of style. For the SD Xserve RAID with 7 x 500GB drives, you should be able to get about 3 streams of 10 bit SD to playback. Here is my recommended configuration:

    Xserve RAID 1: 2 x 7 disk RAID 5’s striped as a RAID 50
    Xserve RAID 2: 1 x 7 disk RAID 5 with 2 slices

    When all is said and done you should have 3 volumes in SANmp Client.

  • Ben Cheng

    February 15, 2006 at 6:04 am

    Hi Nate,

    Thanks for your reply

    Usually, we created 2 volumes for each client, Media + Render

    The reason is, client B is able to capture material for client A, while client A continues working

    I will split XServe RAID 1 into 4 LUNs, 2 on each channel; XServe RAID 2 into 4 LUNs too

    On XServe RAID 1, I will take 1 LUN from each channel to create a volume, striping 2 LUNs across the 2 channels, creating 2 volumes in total

    The HD station will have these 2 volumes

    On XServe RAID 2, I will take 1 LUN to create 1 volume, 4 volumes in total

    The 2 x SD stations will have 2 volumes each

    Cheers,
    Ben Cheng
    Media V
    Singapore

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