• Adobe After Effects Expressions

  Offset position on 900 layers

  Posted by Gon Perdigao on June 11, 2016 at 5:51 pm

  Hello, I have 900 layers that they animate from -5000Z axis to 0.
  I want to offset them by 5 frames, is there a fast and quick way of doing this?
  I remember that grey machine had a tutorial about this, but I can’t find it.

  Can anyone help me?

  Cheers

  Gon Perdigao replied 9 years, 11 months ago 2 Members · 4 Replies
• 4 Replies

• 

  Dan Ebberts

  June 11, 2016 at 6:04 pm

  If you currently have them keyframed, you could add something like this to the position property:

  delay = (index-1)*framesToTime(5);
  valueAtTime(time-delay)

  Dan
• 

  Gon Perdigao

  June 11, 2016 at 6:26 pm

  Dan you are the best!!!!!

  Thanks so much for this.

  If I would and wanna add this expression to the animation // Inertial Bounce (moves settle into place after bouncing around a little)
  n = 0;

  if (numKeys > 0){

  n = nearestKey(time).index;

  if (key(n).time > time){

  n–;
  }
  }
  if (n == 0){

  t = 0;
  }else{

  t = time – key(n).time;

  }

  if (n > 0){

  v = velocityAtTime(key(n).time – thisComp.frameDuration/10);

  amp = .05;
  freq = 4.0;

  decay = 2.0;

  value + v*amp*Math.sin(freq*t*2*Math.PI)/Math.exp(decay*t);

  }else{
  value;
  }

  How could I do it?

  Cheers
• 

  Dan Ebberts

  June 11, 2016 at 8:27 pm

  Try this:

  
delay = (index-1)*framesToTime(5);
myTime = time-delay;
n = 0;
if (numKeys > 0){
n = nearestKey(myTime).index;
if (key(n).time > myTime){
n--;
}
}
if (n == 0){
t = 0;
}else{
t = myTime - key(n).time;
}
if (n > 0){
v = velocityAtTime(key(n).time - thisComp.frameDuration/10);
amp = .05;
freq = 4.0;
decay = 2.0;
valueAtTime(myTime) + v*amp*Math.sin(freq*t*2*Math.PI)/Math.exp(decay*t);
}else{
valueAtTime(myTime);
}


  Dan
• 

  Gon Perdigao

  June 14, 2016 at 8:47 am

  Dan, Thank you so much for your help!
  You just save my life.

  Cheers

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