• Adobe After Effects Expressions

  Can I simplify this expression?

  Posted by Lord Scales on April 27, 2007 at 6:14 pm

  Hi!
  Ok, I connected my Source Text to my Text scale.

  To the scale, I applied this:
  x = Math.abs(Math.sin(time)*100);
  y = 100;
  [x, y]

  Until here, no problem.
  But my source text had a lot of numbers after the dot, like: 84,14709848…

  So I applied Math.round(transform.scale[0]) to round it.

  But I wanted to simplify to 84,1 (84,14709848…) and not to 84 (example).

  So I did this:

  scale = transform.scale[0];
  round = Math.round(scale);
  d = (scale – round)*10;
  dII = .1*Math.round (d);
  fin = round + dII;

  fin

  So, scale was the scale of my layer, and in “round” I rounded it (example: 84,14709848 to 84). In “d” I simply subtract scale and round (84,14709848… – 84 = 0,14709848…), to leave only the numbers after the decimal point and I multiplied them by 10 to give them and integer number (so 0,14709848… became 1,4709848…). In “dII” I round my 1,4709848… to 1 and I divided it by 10 (multiply by 0.1) so it became 0.1. So in “fin” I did the round (value in integers) plus the dII (the number with one number after the decimal point) to round 84,14709848 to 84,1.

  And to round 84,14709848 to 84,14 I used this:

  scale = transform.scale[0];
  scale2 = scale*10
  round = Math.round(scale2);
  d = (scale2 – round)*10;
  dII = .1*Math.round (d);
  fin = (round + dII)*.1;

  fin

  So, I have and impression that I can simplify this a lot. Is it possible or am I crazy?

  Thank you,
  Gustavo.

  Dan Ebberts replied 14 years, 6 months ago 3 Members · 5 Replies
• 5 Replies

• 

  Dan Ebberts

  April 27, 2007 at 6:54 pm

  You’ll like this 🙂

  transform.scale[0].toFixed(1)

  Dan
• 

  Lord Scales

  April 27, 2007 at 7:18 pm

  I almost fainted when I saw that, so simple, so easy…

  I didn’t know toFixed till now, it is incredible to simplify numers (not as incredible as you, Dan).

  It is a good think to add in your Expressioneer’s Design Guide, isn’t it?

  Thank you very much!
• 

  Dan Ebberts

  April 27, 2007 at 7:48 pm

  Yes, thanks for thanks for the suggestion. I’m working on one that uses toFixed();

  Dan
• 

  Nick Depp

  November 5, 2011 at 6:24 am

  1/1+a^n + 1/1+a^-n

  My attempt:
  =1/1+a^n + 1+a^n/1
  =1+{1+a^n(1+a^n)}/1+a^n
  =1+1+2a^n+a^n^2/1+a^n
  =2+2a^n+a^n^2/1+a^n
  let a^n=m
  =2+2m+2m^2/1+m
  =2(1+m+m^2)/1+m

  I don’t know what to do next, the answer is supposed to be 1.
  

  will you please simplify the expression its very urgent i tried on many sites but didn’t get the correct answer according to my mathematics textbook.
• 

  Dan Ebberts

  November 5, 2011 at 8:39 am

  How about this:

  1/(1 + a^n) + 1/(1 + a^-n)
  = ((1 + a^-n) + (1 + a^n))/((1 + a^n)*(1 + a^-n))
  = (2 + a^n + a^-n)/(1 + a^n + a^-n + a^n*a^-n)
  = (2 + a^n + a^-n)/(2 + a^n + a^-n)
  = 1

  Dan

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