[Dan Ebberts]

It’s not particularly simple to set up, but you can do it. I describe one way here:

http://www.motionscript.com/design-guide/marker-sync.html

[Dan Ebberts]

Like this:

c = comp("Comp B");
m = c.marker;
d = c.displayStartTime;
t1txt = m.numKeys > 0 ? timeToFrames(d + m.key(1).time) : "??";
t2txt = m.numKeys > 1 ? timeToFrames(d + m.key(m.numKeys).time) : "??";
t1txt + "-" + t2txt

[Dan Ebberts]

See if this helps:

c = comp("Comp B");
m = c.marker;
d = c.displayStartTime;
t1txt = m.numKeys > 0 ? timeToFrames(d + m.key(1).time) : "??";
t2txt = m.numKeys > 1 ? timeToFrames(d + m.key(2).time) : "??";
t1txt + "-" + t2txt

[Dan Ebberts]

Or, maybe you always want to display the range defined by the Comp B markers with something like this:

m = comp("Comp B").marker;
t1txt = m.numKeys > 0 ? timeToFrames(m.key(1).time) : "??";
t2txt = m.numKeys > 1 ? timeToFrames(m.key(2).time) : "??";
t1txt + "-" + t2txt

[Dan Ebberts]

If you had comp markers in Comp B marking the start and end times, a text expression like this in Comp A would display the current frame (within the range – blank if not in the range). I’m not sure that’s what you’re asking, but it might get you close:

m = comp("Comp B").marker;
txt = "";
if (m.numKeys > 1){
  t1 = m.key(1).time;
  t2 = m.key(2).time;
  if (time >= t1 && time <= t2){
    txt = timeToFrames(time);
  }
}
txt

[Dan Ebberts]

Like this for B:

thisComp.layer("A").text.sourceText.split("\r")[0]

and this for C:

thisComp.layer("A").text.sourceText.split("\r")[1]

[Dan Ebberts]

Try this:

num = effect("Slider Control")("Slider");
num =  "" + Math.round(num/1)*1;
while (num.length < 4) num = "0" + num

[Dan Ebberts]

Expressions don’t have access to work area info. Scripting does, but with a script you’d have to run it every time you need it to update. There may not be a good solution.

[Dan Ebberts]

I think part of the problem is that it’s not hard to conjure up a situation where just rotating on the y axis can’t make the top edge appear horizontal in the camera view, so I think it may be a problem with no solution in some situations.

[Dan Ebberts]

This seems to work, but I’m not sure if it’s what you’re after:

n = [];
for (i = 1; i < 5; i++){
  n.push(thisComp.layer("Control").effect(i)(1));
}
n.sort(function(a,b){return a-b})