[Dan Ebberts]

A couple of things– instead of this:

app.project.item(i).layers.length

I’d use this:

app.project.item(i).numLayers

Also, your section that processes myTextLayer2 uses the text from myTextLayer3.

Dan

[Dan Ebberts]

Since expressions have know way of accessing values they calculated on previous frames, you have to recreate the whole sequence, from frame 0 to the current frame, on each frame. Something like this should work, but you need to be aware that the expression has to do more calculation on each successive frame, so it may grind to a halt if your comp is too long:


seedRandom(index,true);
curVal = Math.floor(random(3))
f = timeToFrames(time);
for (i = 0; i <= f; i++){
curVal += Math.floor(random(1,3));
curVal %= 3;
}
curVal+1


Dan

[Dan Ebberts]

That’s the right function. Your code works fine for me–I’m not sure why it doesn’t work for you. Maybe a permissions thing? Do you have the preference set that allows scripting to access the network?

Dan

[Dan Ebberts]

Unfortunately, once you apply an expression to source text, you’re limited to a single font.

Dan

[Dan Ebberts]

Try it this way:


segMin = 1; //minimum segment duration
segMax = 5; //maximum segment duration
minVal = 100;
maxVal = 130;

end = 0;
j = 0;
while ( time >= end){
j += 1;
seedRandom(j,true);
start = end;
end += random(segMin,segMax);
}
endVal = random(minVal,maxVal);
seedRandom(j-1,true);
dummy=random(); //this is a throw-away value
startVal = random(minVal,maxVal);
s = ease(time,start,end,startVal,endVal);
[s,value[1]]


Dan

[Dan Ebberts]

Is there anything that’s not square pixels?

Dan

[Dan Ebberts]

Hmmm… That’s exactly how it works for me. I can move the camera or 3DLayer, but the expression samples the layer at [100,500] in the camera view. I’m not sure why it doesn’t work for you.

Dan

[Dan Ebberts]

I got this to work:

myLayer = thisComp.layer(“3DLayer”);
p = myLayer.fromCompToSurface([100,500]);
myLayer.sampleImage(p,[0.5,0.5])

Dan

[Dan Ebberts]

You are correct about the expression not being able to hold the value, so your expression will need to loop through the “time” fields until it finds the most recent, previous value. If it’s a lot of data, you might be able to optimize it somewhat with a binary search, but that might be overkill.

Dan

[Dan Ebberts]

Try this:

L = thisComp.layer(“Box”);
r = L.sourceRectAtTime();
p = L.toComp([r.left + r.width/2,0]) – position;
[p[0],value[1]]

Dan