[Dan Ebberts]

Glad you like ’em, guys. 🙂

Dan

[Dan Ebberts]

An even easier way, if you want both sides of your layer to be solid colors, would be to just use the Fill effect, with this expression applied to the Color parameter:

frontColor = [0,0.5,0.5,1]; // turquoise
backColor = [0.5,0.5,0,1]; // dark yellow
if (toCompVec([0, 0, 1])[2] > 0 ) frontColor else backColor

In case you don’t know, in expressions colors are represented by arrays [r,g,b,a] wher r, g, and b are the amounts of red, green, and blue, expressed as numbers between 0 and 1. a is the alpha, just leave it set to 1.

Dan

[Dan Ebberts]

An even easier way, if you want both sides of your layer to be solid colors, would be to just use the Fill effect, with this expression applied to the Color parameter:

frontColor = [0,0.5,0.5,1]; // turquoise
backColor = [0.5,0.5,0,1]; // dark yellow
if (toCompVec([0, 0, 1])[2] > 0 ) frontColor else backColor

In case you don’t know, in expressions colors are represented by arrays [r,g,b,a] wher r, g, and b are the amounts of red, green, and blue, expressed as numbers between 0 and 1. a is the alpha, just leave it set to 1.

Dan

[Dan Ebberts]

This should work. Apply Fill to your layer. Then apply CC Composite to the layer and apply this expression to the effect’s Opacity parameter:

if (toCompVec([0, 0, 1])[2] > 0 ) 100 else 0

Dan

[Dan Ebberts]

This should work. Apply Fill to your layer. Then apply CC Composite to the layer and apply this expression to the effect’s Opacity parameter:

if (toCompVec([0, 0, 1])[2] > 0 ) 100 else 0

Dan

[Dan Ebberts]

Assuming your hexagons are layers 1 through 18, this should work:

numCols = 18;
col = (index-1)%numCols + 1;

Dan

[Dan Ebberts]

Assuming your hexagons are layers 1 through 18, this should work:

numCols = 18;
col = (index-1)%numCols + 1;

Dan

[Dan Ebberts]

I think I’d do it with an expression like this:

col = 1; // column number for this layer (1 thru ?)
delay = .5; // per-column delay (in seconds)

thisComp.layer(“Null 1”).rotationY.valueAtTime(time – (col-1)*delay)

The value for “col” would either have to be hard-coded into the expression for each hexigon or calculated based on the layer index and the total number of columns (we can help with that if you need it).

Dan

[Dan Ebberts]

I think I’d do it with an expression like this:

col = 1; // column number for this layer (1 thru ?)
delay = .5; // per-column delay (in seconds)

thisComp.layer(“Null 1”).rotationY.valueAtTime(time – (col-1)*delay)

The value for “col” would either have to be hard-coded into the expression for each hexigon or calculated based on the layer index and the total number of columns (we can help with that if you need it).

Dan

[Dan Ebberts]

Your details are a little sketchy, but maybe this will help. This Position expression example will have your “delayed” layer start doing (at its first layer marker) what Null 1 does at frame zero. So you just keyframe Null 1 and set a layer marker on the other layer where you want the motion to start.

control = thisComp.layer(“Null 1”);
if (marker.numKeys > 0){
t = time – marker.key(1).time;
control.position.valueAtTime(t);
}else{
value;
}

Dan