[Andrei Popa]

If you want to also consider the actual value of the property, you must add it. So the last line should be “value + ” whatever you have there.

Andrei
My Envato portfolio.

[Andrei Popa]

Or we can make it like this so it looks even better:

var selection = app.project.selection;
var mySelectedItems = findSel (selection);
alert(mySelectedItems);

function findSel(selection){
var selAry = []

for (var i=0;i<selection.length;i++){
var currentItem= selection[i];

if(currentItem.typeName != "Folder"){
selAry.push(currentItem);
}else{
selAry.push(currentItem);
folderSearch(currentItem);
}
}

function folderSearch(myFolder){

for (var i=1; i<=myFolder.items.length; i++){
var curFolderItem = myFolder.items[i];

if(curFolderItem.typeName != "Folder"){
selAry.push(curFolderItem);
}else{
selAry.push(curFolderItem);
folderSearch(curFolderItem);
}
}
}

return selAry;
}

Andrei
My Envato portfolio.

[Andrei Popa]

Please try to use as few global variables as possible. With many of them, it’s easy to just see where they have gone sideways as value. Just declare values locally and pass them as function argumentts. Also, try to put var in front of the for variable. I will try to reproduce your code as i would make it.

var selection = app.project.selection;

function findSel(selection){
var selAry = []

for (var i=0;i<selection.length;i++){
var currentItem= selection[i];

if(currentItem.typeName != "Folder"){
selAry.push(currentItem);
}else{
selAry.push(currentItem);
folderSearch(currentItem);
}
}

function folderSearch(myFolder){

for (var i=1; i<=myFolder.items.length; i++){
var curFolderItem = myFolder.items[i];

if(curFolderItem.typeName != "Folder"){
selAry.push(curFolderItem);
}else{
selAry.push(curFolderItem);
folderSearch(curFolderItem);
}
}
}

return selAry;
}

var mySelectedItems = findSel (selection);
alert(mySelectedItems)

The mySelectedItems variable is the array that contains the selected items. Last alert is just for checking.

Andrei
My Envato portfolio.

[Andrei Popa]

Hey. Thank you very much for the kind word, it really means a lot.

Now. To make the letters also italic, just click the add(from where you added expression selector), select Property and then Skew. Now modify the Skew value to what you wish.

Andrei
My Envato portfolio.

[Andrei Popa]

Nvm, i got this. The kind of problem that does not go out of your head…

var t = text.sourceText;
var splitText = t.split("\r");
var regex = /\(([^)]+)(?=\))/g;

function indexMatched(index){
var matched = false;
var match;
while ((match = regex.exec(t)) !== null){
matched |= match.index<index & index<match.index+match[0].length;
}
return matched;
}

function placeInLines(index){
i=0;
maxIndex = 0;
while(index>maxIndex){
maxIndex += splitText[i].length;
i+=1;
}
return i-2;
}

indexMatched(textIndex+placeInLines(textIndex)) ? 100 : 0;

Still, i think there are better solutions. I would like to see someone solve this in a more elegant manner.

Andrei
My Envato portfolio.

[Andrei Popa]

That is because the amount selector does not count the enters at the end of the line. This works for multiple paratheses, as long as they are only on the first line or in a textbox. I can’t think of a solution right now. The best i can come up with is split into multiple layers so you don’t need to use enter before any paratheses.

Andrei
My Envato portfolio.

[Andrei Popa]

I am pretty sure you put the expression where it was not supposed to be.

Here is a short screen rec.
13527_tutorial.mp4.zip

Andrei
My Envato portfolio.

[Andrei Popa]

Without the i part…

var t = text.sourceText;
var regex = /\(([^)]+)(?=\))/g;

function indexMatched(index){
var matched = false;
var match;

while ((match = regex.exec(t)) !== null){
matched |= match.index

Andrei
My Envato portfolio.

[Andrei Popa]

I’m not that good with regular expressions, but i remembered this post of Oleg Pirogov and after few searches on Stack Overflow i came up with this. Worked on my test. I used two occurences, one with space and one without.

So add a text animator, fill color, rgb. To this animator add selector>expression. In the expression field write this:

var t = text.sourceText;
var regex = /\(([^)]+)(?=\))/g;

function indexMatched(index){
var matched = false;
var match;
var i=[];

while ((match = regex.exec(t)) !== null){
matched |= match.index

Andrei
My Envato portfolio.

[Andrei Popa]

Depends if your y grows or dimishes. Did not think that through. If your y is smaller at the 3rd key, you should change the last 2 values of the linear function like this:

if (time>key(2).time){
x = linear(position[0], key(2).value[0], key(3).value[0], key(2).value[0], thisComp.layer("Control Null")("Transform")("Position")[0]);
y = linear(position[1], key(2).value[1], key(3).value[1], thisComp.layer("Control Null")("Transform")("Position")[1], key(2).value[1]);
[x,y]
}else{
value
}

Andrei
My Envato portfolio.