• Adobe After Effects Expressions

  3D Lissajous expression In after effects

  Posted by Valerio Rubino on April 5, 2018 at 10:48 pm

  Hi everyone,
  I just came across an old post of this forum; https://forums.creativecow.net/thread/227/12642
  Which explain how realize this 3d curve generated by an emitter and trapcode particular. what i’m trying to do is a lissajous 3d path in after effects or an emitter wich create a kind of stroke showing the lissajous curve. I was trying to “translate” this math expression(https://www.mathcurve.com/courbes3d/lissajous3d/lissajous3d.shtml) into a after effects expression but i do not manage in this.

  Thanks in advance,

  Valerio.

  Valerio Rubino replied 8 years, 1 month ago 2 Members · 2 Replies
• 2 Replies

• 

  Kalleheikki Kannisto

  April 13, 2018 at 5:44 pm

  Would this help?

  (from: https://www.davdata.nl/math/lissajous3d.html)

  3D Lissajous functions have the general form
  x = cos(..t)…
  y = sin(..t)…
  z = sin(..t)…

  Sin and cos functions are interchangeble.

  Example
  x = 0.5cos(5t) + 0.5cos(4t)
  y = 0.5sin(5t) + 0.5sin(t)
  z = sin(2t)

  Kalleheikki Kannisto
  Senior Graphic Designer
• 

  Valerio Rubino

  April 14, 2018 at 11:51 am

  Hi, thanks Kalleheikki Kannisto for this help. a couple of days ago i managed with this function. what I did is write the expression in the position property of a NULL and after I’ve linked to this layer the position (xyz) of cc particle word. I change the comp setting with 120fps because the line painted from particle wasn’t really smooth.

  however, thanks to this help! I’ll try to give to this community what I know.

  t=time*8;

  a=1;
  b=1.3;
  n=3/2;

  x=a*Math.cos(t)
  y=a*Math.sin(t)
  z=b*Math.cos(n*t);

  value + [x,y,z]*130;
  _____________________

  x=thisComp.layer("movement").transform.position[0]-thisComp.width/2;

  y=thisComp.layer("movement").transform.position[1]-thisComp.width/2;
  y/thisComp.width

  z=thisComp.layer("movement").transform.position[2]-thisComp.width/2;
z/thisComp.width

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