• Adobe After Effects Expressions

  “IF” Statement Does Not Work

  Posted by Marius Gudzevicius on May 4, 2017 at 8:15 am

  Hello everyone!

  I’ve been trying to write an expression for position. I want to make it move down when that object’s scale is [100,100]. Scale has an expression that makes it scale from 0 to 100 at any random time in composition. The thing is when I write “if” statement in position expression to check if the scale is 100 or 0 it always works as 100 and I don’t understand why. Can anyone help with that?

  //scale expression for the object:
seedRandom(1,true);
rand = random()*thisComp.duration;
if (time>=rand){[100,100];}
else{[0,0];}

  //Position expression for the same object:
scale = content("Group 1").transform.scale; //pickwhiped from scale
t = time;
seedRandom(0,true);
if (scale = [0,0]) {
y=0; x=0;
value + [x,y]};
if (scale = [100,100]){
y = random()*10 * t ;
x = 0;
value + [x,y];}

  Marius Gudzevicius replied 9 years, 4 months ago 2 Members · 2 Replies
• 2 Replies

• 

  Dan Ebberts

  May 4, 2017 at 1:22 pm

  For one thin, your if test needs to use the double equal sign operator, like this:

  if (scale == [0,0]) {

  I haven’t tested this, but I think I’d structure the position expression more like this:

  
s = content("Group 1").transform.scale;
if (s[0] < 50){
value
}else{
seedRandom(0,true);
y = random(10) * time;
value + [0,y]
}


  Dan
• 

  Marius Gudzevicius

  May 4, 2017 at 1:43 pm

  That works perfectly! Thank you Dan!

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