• Adobe After Effects Expressions

  Line break expression is eating one character

  Posted by David Cabestany on June 21, 2016 at 4:17 pm

  I’m using the expression below to generate random text and I need to break every 8 characters, which it does for the first line, but then every line after that breaks at 7.

  I tried changing the value to test the expression and the same happens, if I enter 10, the line breaks at 9 and so on.
  I changed the font to see if I need a mono spaced font and the same happened.

  My text box is more than enough to cover for the length of the lines.

  Can anyone tell me what’s going on?

  Thanks.
  D.

  rate=5;
totalChar=64;
lineBreak=10;
posterizeTime(rate);
selectionSet=["8","2","1","3","0","6"];
txt="";
for(i=0; i<totalChar; i++)
{
randomNumber=random(0,selectionSet.length);
txt += selectionSet[Math.floor(randomNumber)];
if (txt.length % lineBreak == 0) txt += "\r";
}
txt

  David Cabestany replied 10 years, 2 months ago 2 Members · 2 Replies
• 2 Replies

• 

  Dan Ebberts

  June 21, 2016 at 4:49 pm

  I think you just need to change the line break line to something like this:

  if (i > 0 && (i+1)%lineBreak == 0) txt += “\r”;

  Dan
• 

  David Cabestany

  June 21, 2016 at 4:55 pm

  Yes sir, that was it.

  Thanks!
  D.

Reply to this Discussion! Login or Sign Up