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One layer reading another layer’s expression?
I have an expression that uses out_point of a layer to trigger a change in opacity.
If I pickwhip another layer’s opacity to that expression, it’ll use the source layer’s out_point. It copies that layer’s Opacity value (0~100) but not the expression itself.
How can I get another layer to use the expression of the source layer, but not the value of that expression for that source layer? So each layer will use its own out_point, but all reading a common source expression?
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3 Replies
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There’s no way for an expression to access an expression in another property. There is a hack where you can store a common expression as text in a text layer and have each property retrieve that text and use eval() to evaluate the expression, but it’s probably more trouble than it’s worth.
Dan
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Argh. That’s too bad. I’m assuming the eval() function of reading a text file off a drive has a big performance hit — esp if you have a ton of layers reading it.
Whatever happened to Adobe Capsules? Weren’t they supposed to give nodal-type reusable expressions, but without the complexity of a true nodal system?
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>…I’m assuming the eval() function of reading a text file off a drive…
Oh yeah, that would be another way. 🙂
Dan
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