• Adobe After Effects Expressions

  incrementing by 100

  Posted by Orme Dominique on February 4, 2013 at 9:07 pm

  This is driving me nuts, I can’t seem to get Dan’s currency script to increment by 100 while still having commas and being able to go 5000000. Can someone help me out with this? Banging head agains wall.

  numDecimals = 2;
  commas = true;
  dollarSign = true;
  beginCount = -1999;
  endCount = 1999;
  dur = 4;

  t = time – inPoint;
  s = linear (t, 0, dur, beginCount, endCount).toFixed(numDecimals);

  prefix = “”;
  if (s[0] == “-“){
  prefix = “-“;
  s = s.substr(1);
  }
  if(dollarSign) prefix += “$”;

  if (commas){
  decimals = “”;
  if (numDecimals > 0){
  decimals = s.substr(-(numDecimals + 1));
  s = s.substr(0,s.length – (numDecimals + 1));
  }
  outStr = s.substr(-s.length, (s.length-1)%3 +1);
  for (i = Math.floor((s.length-1)/3); i > 0; i–){
  outStr += “,” + s.substr(-i*3,3);
  }
  prefix + outStr + decimals;
  }else{
  prefix + s;
  }

  numDecimals = 2;
commas = true;
dollarSign = true;
beginCount = -1999;
endCount = 1999;
dur = 4;

  t = time - inPoint;
  s = linear (t, 0, dur, beginCount, endCount).toFixed(numDecimals);

  prefix = "";
  if (s[0] == "-"){
  prefix = "-";
  s = s.substr(1);
  }
  if(dollarSign) prefix += "$";

  if (commas){
decimals = "";
if (numDecimals > 0){
decimals = s.substr(-(numDecimals + 1));
s = s.substr(0,s.length - (numDecimals + 1));
}
outStr = s.substr(-s.length, (s.length-1)%3 +1);
for (i = Math.floor((s.length-1)/3); i > 0; i--){
outStr += "," + s.substr(-i*3,3);
}
prefix + outStr + decimals;
}else{
prefix + s;
}

  Orme Dominique replied 13 years, 7 months ago 2 Members · 2 Replies
• 2 Replies

• 

  Dan Ebberts

  February 4, 2013 at 9:42 pm

  Try changing the line that defines variable s from this:

  s = linear (t, 0, dur, beginCount, endCount).toFixed(numDecimals);

  to this:

  s = (Math.floor(linear (t, 0, dur, beginCount, endCount)/100)*100).toFixed(numDecimals);

  Dan
• 

  Orme Dominique

  February 5, 2013 at 8:42 pm

  Worked like a charm. Now I just need to start working these out on my own. Thanks for all your help, Dan.

Reply to this Discussion! Login or Sign Up