Absolutely second this – 13 years on and this is still a lifesaver.

Thank you

Oh wow. I think this is all fresh enough in my mind that I can restitch it with that and see if it works. I absolutely agree that making things more efficient will help in the long run.

Thank you

HA!!

Done it I think.

For some reason my equation to get the angle via inverse sin had the values dividing the wrong way – I was dividing the base length by the hypotenuse or the other way round – which meant that I was coming out with a value greater than 1 which, it appears, an inverse sine can’t do (I have no idea how this works btw).

I swapped…

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Ah… spoke too soon!

As Mark was doing, I’m trying to figure out the angle of a right angled triangle from the lengths of the sides using inverse sin.

I’ve followed all of the replies here and am getting somewhere all up until I try and call the inverse sin using …

Math.asin().

…where the expression gives me an error. Here is the code…

//half…

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Mark (and everyone),

THANK YOU! I’m doing exactly the same thing and have been hitting my head against a wall for a day or so.

You guys are all so great.

Jim